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    Hom-Leibniz Superalgebras

    2014-07-19 11:47:55SHENZhenjunWEIZhuZHANGQingcheng

    SHEN Zhen-jun,WEI Zhu,ZHANG Qing-cheng

    (Mathematics and Statistics,Northeast Normal University,Jilin 130024,China)

    Hom-Leibniz Superalgebras

    SHEN Zhen-jun,WEI Zhu,ZHANG Qing-cheng

    (Mathematics and Statistics,Northeast Normal University,Jilin 130024,China)

    We gived the def i nition of Hom-Leibniz superalgebra and studied its basic properties.In particular,the derivations of Hom-Leibniz Superalgebras are portrayed in detail.

    Hom-Leibniz superalgebras;derivations;basic properties

    §1.Introduction

    The theory of Hom-algebras originated from the introduction of the notion of a Hom-Lie algebras by J T Hartwig,D Larsson and S D Silvestrov in[1],in the study of algebraic structures describing some q-deformation of the Witt and the Virasoro algebras.Hom-Lie superalgebras and other Hom-algebras structures have been widely investigated these last years,a Hom-Lie superalgebra is a triple(G,[·,·],α),which G is a vector superspace,α is a endomorphism of G and the skew-symmetric bracket satisf i es an α-twisted variant of the Jacobi identity,Lie algebras are special cases of Hom-Lie algebras in which α is the identify map.Hom-Lie superalgebras were studied in[3]and cohomology theory of Hom-Lie superalgebras and Hom-leibniz algebras were studied in[9,11,13].The concept of Leibniz algebras was f i rst introduced by Loday[2]in the study of the so-called Leibniz homology of Lie algebra as a“noncommuctive”analog of Lie algebra homology found by Cuvier[4]and Loday[5]respectively.And the concept of Leibniz superalgebras and its cohomology were f i rst introduced by Dzhumadil’daev in[6],some theory of superdialgebras and Leibniz superalgebra and their cohomology were studied in[7-8]and the central extensions,the universal central extensions of Leibniz superalgebras were constructed. The purpose of this paper is to study the basic properties of Hom-Leibniz superalgebras,and portrayed derivations of Hom-Leibniz superalgebras.

    §2.The Basic Properties of Hom-Leibniz Superalgebras

    In this section,we f i rst recall the notion of Hom-Leibniz superalgebras and then give some construction of the Hom-Leibniz superalgebras.

    Def i nition 2.1A Hom-Leibniz superalgebra is a triple(G,[·,·],α)consisting of a superspace G,an even bilinear map(bracket)[·,·]:G×G→G and an even superspace homomorphism α:G→G satisfying

    for all homogeneous elements x,y,z∈G.

    When α=Id,we call G is a Leibniz superalgebra.The identity(2)is called Hom-Leibniz superidentity.

    Proposition 2.2Given two Hom-Leibniz superalgebras(G,[·,·],α)and(V,[·,·],β)and there is a Hom-Leibniz superalgebra(G⊕V,[·,·],α+β),where the bilinear map[·,·]:(G⊕V)?2→G⊕V is given by

    and the even multiplicative superspace homomorphism α+β:G⊕V→G⊕V is given by

    ProofWe just check that α+β is an even superspace homomorphism and(G⊕V,[·,·],α+β) satisf i es the Hom-Leibniz superidentity.In fact,we can obtain

    and

    Therefore,(G⊕V,[·,·],α+β)is a Hom-Leibniz superalgebra.

    Def i nition 2.3Let(G,[·,·],α)and(V,[·,·],β)be two Hom-Leibniz superalgebras.An even homomorphism φ:G→V is said to be a morphism of Hom-Leibniz superalgebras if satisfying

    for anyμ,ν∈G.

    Denote by ?φ={(u,φ(u)|u∈G}.

    Proposition 2.4A linear map φ:(G,[·,·],α)→(V,[·,·],β)is a morphism of Hom-Leibniz superalgebras if and only if the graph ?φ?G⊕V is a Hom-Leibniz sub-superalgebra of (G⊕V,[·,·],α+β).

    ProofLet φ:(G,[·,·],α)→(V,[·,·],β)be a morphism of Hom-Leibniz superalgebras,then for any u1,u2∈G,we have

    Thus the graph ?φis closed under the bracket operation[·,·].Furthermore,by(4),we have

    which implies that(α+β)(?φ)??φ.Thus ?φis a Hom-Leibniz sub-superalgebras of(G⊕V,[·,·],α+β).

    Conversely,if the graph ?φ?G⊕V is a Hom-Leibniz sub-superalgebra of(G⊕V,[·,·],α+β), then we have

    that is

    Furthermore,(α+β)(?φ)??φyields that

    which is equivalent to the condition β?φ=φ?α.Therefore φ is a morphism of Hom-Leibniz superalgebras.

    Proposition 2.5Let(G,[·,·])be a Leibniz superalgebra and α:G→G be an even Leibniz superalgebra endomorphism.Then(G,[·,·]α,α),in which[·,·]α=[α(x),α(y)]is a Hom-Leibnizsuperalgebra.Moreover,it is supposed that(G′,[·,·]′)is another Leibniz superalgebra and α′:G′→G′is an even Leibniz superalgebra endomorphism,and if f:G→G′is a Leibniz superalgebrsa morphism that satisf i es f?α=α′?f,then

    is a morphism of Hom-Leibniz superalgebras.

    ProofWe show that the(G,[·,·]α,α)satisf i es the Hom-Leibniz superidentity.Indeed

    The second assertion follows from

    Example 2.6Let G=Gˉ0⊕Gˉ1be a 2-dimensional superspace,where Gˉ0is generated by e1and Gˉ1is generated by e2.The triple(G,[·,·],α)is a Hom-Leibniz superalgebra def i ned by[e2,e1]=ke2with α(e1)=e1,α(e2)=ke2.

    Example 2.7Let G=Gˉ0⊕Gˉ1be a 3-dimensional superspace,where Gˉ0is generated by e1,e2and Gˉ1is generated by e3.The triple(G,[·,·],α)is a Hom-Leibniz superalgebra def i ned by[e2,e2]=e1,[e3,e2]=4e3with α(e1)=e1,α(e2)=e1+e2,α(e3)=2e3.

    Theorem 2.8Let(G,[·,·],α)be a Leibniz superalgebra and β:G→G be an even Leibniz superalgebra endomorphism.Then(G,[·,·]β,β?α)is a Hom-Leibniz superalgebra, where[x,y]β=β([x,y]).

    ProofFor all x,y,z∈G,we have

    and

    so(G,[·,·]β,β?α)satisf i es the Hom-Leibniz superidentity.Therefore,(G,[·,·]β,β?α)is a Hom-Leibniz superalgebra.

    RemarkWhen α=Id,that is Proposition 2.5.

    §3.Derivations of Hom-Leibniz Superalgebras

    Let(G,[·,·],α)be a Hom-Leibniz superalgebra,denoting by αkthe k-times composition of α,i.e.,αk=α?α···?α(k-times).In particular,α?1=0,α0=Id,α1=α.

    Def i nition 3.1For any k≥?1,we call D∈(EndG)i,where i∈Z a αk-derivation of the Hom-Leibniz superalgebra(G,[·,·],α),if

    and

    for all homogeneous elements x,y∈G.

    We denote by Derαk(G)=(Derαk(G))ˉ0⊕(Derαk(G))ˉ1the set of αk-derivations of the Hom-Leibniz superalgebra(G,[·,·],α)and

    For any homogeneous element a∈G,satisfying α(a)=a,def i ne adk(a)∈End(G)by

    Notion that adk(a)and a are of the same parity.

    Theorem 3.2Let(G,[·,·],α)be a Hom-Leibniz superalgebra.Then adk(a)is an αk+1-derivation,which we call inner αk+1-derivation.

    ProofIndeed we have

    and

    Therefore,adk(a)is a αk+1-derivation.

    We denote by Innαk(G)the set of inner αk-derivations,i.e.,

    For any D∈Der(G)and D′∈Der(G),def i ne their commutator[D,D′]as usual

    Lemma 3.3For any D∈(Derαk(G))iand D′∈(Derαs(G))j,where k+s≥?1 and (i,j)∈Z22,we have

    ProofFor any x,y∈G,we have

    Since D and D′satisfy α?D=D?α and α?D′=D′?α,we have

    It is easy to verify that α?[D,D′]=[D,D′]?α,which leads to[D,D′]∈Derαk+s(G))|D|+|D′|.

    RemarkObviously,we have

    Thus for any D,D′∈Derα-1(G),we have[D,D′]∈Derα-1(G).

    Proposition 3.4With the above notations,when α satisf i es α2=α and(Der(G),[·,·],α′) is a Hom-Leibniz superalgebra,in which the bracket[·,·]is def i neted by

    and

    ProofFor any x,y∈G,D∈Der(G),we have

    that is α′(D)∈(Derαk+1(G)).Then we show that α′is a homomorphism.Indeed

    For any D1,D2,D3∈Der(G),we have

    and

    Since α?D1=D1?α,α?D2=D2?α,α?D3=D3?α,so

    that is,[[D1,D2],α′(D3)]=[α(D1),[D2,D3]]+(?1)|D2||D3|[[D1,D3],α?(D2)].We know that (Der(G),[·,·],α′)is a Hom-Leibniz superalgebra.

    RemarkWhen omitting the condition α2=α,we know that Der(G)is a Leibnizsuperalgebra.

    Finally,we consider extensions of Hom-Leibniz superalgebra(G,[·,·],α)using derivations. For any D∈Der(G),consider the vector space?G=?Gˉ0⊕?Gˉ1,where?Gˉ0=Gˉ0⊕?D,?Gˉ1=Gˉ1? is a real f i eld.Def i ne a skew-symmetric bilinear bracket operation[·,·]Don?G by

    [μ+mD,ν+nD]D=[μ,ν]+mD(ν)?(?1)|D||μ|nD(μ),?μ,ν∈G,m,n∈?.

    Def i ne αD∈End(G⊕?D)by αD(μ+mD)=α(μ)+mD.

    Theorem 3.5With the above notions,(?G,[·,·]D,αD)is a Hom-Leibniz superalgebra if and only if D is an α-derivation of the Hom-Leibniz superalgebra(G,[·,·],α).

    ProofFor anyμ,ν∈G,n,m∈?,we have

    and

    Since α is a morphism of Hom-Leibniz superalgebra,thus αDis a morphism of Hom-Leibniz superalgebra,D?α=α?D,then αD[(μ,mD),(ν,nD)]D=[αD(μ,mD),αD(ν,nD)]D.On the other hand,we can get

    Therefore,it is obvious that the Hom-Leibniz superidentity is satisf i ed if and only if

    Thus(?G,[·,·]D,αD)is a Hom-Leibniz superalgebra if and only if D is an α-derivation.

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    tion:16E40,17B56,17B68,17B70

    1002–0462(2014)04–0583–09

    date:2013-03-11

    Supported by the National Natural Science Foundation of China(10871057,11171055)

    Biographies:SHEN Zhen-jun(1986-),male,native of Xinyang,Henan,a M.S.D.of Northeast Normal University,engages in Lie algebras and Lie superalgebras;ZHANG Qing-cheng(1960-),male,native of Xinyang, Henan,a professor of Northeast Normal University,engages in Lie superalgebras(corresponding author).

    CLC number:O125.5Document code:A

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