Observations on Irreducible Sets and Sober Spaces

CHEN Dong-li,ZHANG Yan

(1.School of Science,Xi’an University of Architecture and Technology,Xi’an 710055,China; 2.Huaqing College,Xi’an University of Architecture and Technology,Xi’an 710043,China)

Observations on Irreducible Sets and Sober Spaces

CHEN Dong-li1,ZHANG Yan2

(1.School of Science,Xi’an University of Architecture and Technology,Xi’an 710055,China; 2.Huaqing College,Xi’an University of Architecture and Technology,Xi’an 710043,China)

This paper,using the monads theory in the topological space,gives a new characterization of irreducible sets in the nonstandard enlarged models.Further,the discretization expression of Sober topological spaces is presented.

monad;irreducible set;Sober space;discretization

§1.Introduction

The monad of a point(set)in topological spaces is a very important concept,which can be used for researching the properties of topological spaces by nonstandard analysis,especially separation[1].It is a generalization of“inf i nitesimal”in general topological spaces[2]and is applicable for discretization expression for many topological properties.For example,the topological space(X,τ)is a T2-sapce(Hausdorf f)if ffor any x,y∈X,if x/=y,then m(x)∩m(y)/=?,where m(x)is the monad of x.Sober property between T0and T2but independent of T1is a special separation and has important applications in continuous spectrum[3].

In this paper,using monads theory,we will give the expressions of irreducible set and Sober space in the nonstandard enlarged models.Throughout this paper we suppose that the topological space X is the subset of individuals S of the standard universe U[4]and thus X??X.

Def i nition 1.1[5]Assume that?U is a nonstandard model of U.?U is called the nonstandard enlarged model of U if for any collection{Ai|i∈I}with f i nite intersection property such that

Remark 1.1Collection{Ai|i∈I}has the f i nite intersection property if ffor any f i nite subfamily

Def i nition 1.2[5]Assume that(X,τ)is a topological space and τxis the open neighborhood systems of x∈τ.Then m(x)=G is called the monad of x.

Remark 1.2y∈X is called a near standard point in?X if there exists a x∈X such that y∈m(x).Denote st(y)={x∈X:y∈m(x)}and y≈x for y∈m(x)[6].

Lemma 1.1Assume that A?X and A stands for the closure of A.Then

ProofIf x∈A,then G∩A/=?,G∈τx.Then{G∩A|G∈τx}has the property of fi nite intersection.Due to this result,

On the other hand,if m(x)∩?A/=?,then?G∩?A/=?,G∈τx.Using the transfer principle[7],G∩A/=?and thus x∈A.

From Lemma 1.1,it is not difficult to obtain that if A?X,then st(?A)=A.

De fi nition 1.3[8]Assume that(X,τ)is a topological space and A?X is a nonempty closed set.A is called the irreducible closed set if A=F1∪F2implies that A=F1or A=F2, where F1and F2are closed sets.

Obviously,for each x∈X,{x}?is the irreducible closed set,where“?”represents the closure operator.

De fi nition 1.4The topological space(X,τ)is called a Sober space if each irreducible closed set A has the form of{x}?,where x∈X.

§2.Main Results

In this section,we give new characterizations of irreducible set and Sober space by monads theory.

Lemma 2.1Let A be a closed subset of topological space(X,τ).Then A={x}?if f x∈A and m(x)?m(y)for all y∈A.

Proof(Necessity)A={x}?implies x∈A.Using Lemma 1.1,for each y,we have that x∈m(y)and thus m(x)?m(y).

(Sufficiency)By the given conditions,x∈m(y)for all y∈A.Again by Lemma 1.1, y∈{x}?.Since A is closed and x∈A,A={x}?.

Lemma 2.2[5](X,τ)is a T0-space if fx=y is equivalent to m(x)=m(y)for any x,y∈X.

Theorem 2.1Let the conditions in Lemma 2.1 hold.A is irreducible if f?.

Proof(Necessity)Suppose that A is a irreducible closed set.Choose x,y∈A,G1∈τx,G2∈τy.If A∩G1∩G2=?,then A=(A?G1)∪(A?G2).The irreducibility of A implies that

Then,A∩G1=?or A∩G2=?.This leads to a contradiction.Therefore,

Since G1and G2are arbitrary,?A∩m(x)∩m(y)/=?.Consequently,

(Sufficiency)Suppose,by contradiction,that A is reducible.By the def i nition of the irreducible set,there exist closed sets F1,F2such that

Choose x∈A?F1and y∈A?F2.By the given conditions,there is α∈?A such that α∈μ(x)∩μ(y).Then,α∈?X??F1and α∈?X??F2.Thus,we obtain that α∈(?X?F1)∩(?X?F2)=?X??(F1∪F2)=?X??A,a contradiction.

Using Theorem 2.1,we now give a nonstandard expression of Sober space.

Theorem 2.2Let(X,τ)be a topological space.X is a Sober space if ffor any closed set

Proof(Necessity)Let A be a closed subset of X such thatTheorem 2.1,A is a irreducible closed set.Thus,there exists x∈X such that A={x}?. Lemma 2.1 yields that m(x)?m(y),y∈A.Hence(Sufficiency)Assume that A?X is a irreducible closed set.Let.Then x∈A and m(x)?m(y)for y∈A.From Lemma 2.1,we have A={x}?.

Corollary 2.1If(X,τ)is a Hausdor ffspace,then it is a Sober space.

ProofLet A?X be a irreducible closed set.If there exist x,y∈A and x/=y,then m(x)∩m(y)=?since X is Hausdor ff.This contradicts with Theorem 2.1.Therefore,there must be x∈X such that A={x}={x}?and thus(X,τ)is a Sober space.

Corollary 2.2If(X,τ)is a Sober space,then it is a T0-space.

ProofLet x,y∈X and m(x)=m(y).It suffices to show x=y.Let A={x,y}.Since m(x)=m(y),A∩m(x)∩m(y)/=?.By Theorem 2.1,A={x,y}?is irreducible.Further,the fact that X is a Sober space implies x=y.It follows from Lemma 2.2 that(X,τ)is T0.

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tion:03H05

1002–0462(2014)04–0501–04

date:2012-11-26

Supported by the Natural Science Foundation of Shaanxi Province(2007A12);Supported by the Scientif i c Research Foundation of Shaanxi Educational Committee(11JK0507)

Biography:CHEN Dong-li(1963-),male,Xi’an,Shaanxi,a professor of Xi’an University of Architecture and Technology,M.S.D.,engages in nonstandard analysis.

CLC number:O141.41Document code:A