Ground States to the Generalized Nonlinear Schr¨odinger Equations with Bernstein Symbols

Jinmyoung Seokand Younghun Hong

1 Department of Mathematics,Kyonggi Univeristy,Suwon 16227,Korea

2 Department of Mathematics,Chung-Ang University,Seoul 06974,Korea

Abstract. This paper concerns with existence and qualitative properties of ground states to generalized nonlinear Schr¨odinger equations (gNLS) with abstract symbols.Under some structural assumptions on the symbol,we prove a ground state exists and it satisfies several fundamental properties that the ground state to the standard NLS enjoys.Furthermore,by imposing additional assumptions,we construct,in small mass case,a nontrivial radially symmetric solution to gNLS with H1-subcritical nonlinearity,even if the natural energy space does not control the H1-subcritical nonlinearity.

Key Words: Generalized NLS,solitary waves,variational methods,Bernstein symbols.

1 Introduction

We consider the generalized nonlinear Schr¨odinger equation (NLS for abbreviation) of the form

In this article,we are concerned with the ground state solution to the generalized NLS(1.1). By a ground state,we mean a standing wave solution of the form

which minimizes the value of the action integral. A rigorous definition of a ground state shall be given in Section 4. As for the standard NLS,i.e.,the caseP(λ)=λ,inserting the standing wave ansatz(1.2)into(1.1),we get the standard stationary NLS

In this case, the theory of ground states has been almost completed during several decades. A criteria for their existence and nonexistence, depending on the range ofμandp, is established in [1,22,23]. Qualitative properties of ground states, such as positiveness,radial symmetry,monotonicity,and uniqueness have been proved in[4,13,14].

With a general symbolP,the stationary generalized NLS is given by

In this paper,we are interested in finding general conditions on the symbolPwhich allow ground states to the generalized NLS (1.4) to have the same kinds of qualitative properties. We propose the following structural assumptions for the symbolP:

(H1)P:[0,∞)→[0,∞)is continuous on[0,∞)and smooth on(0,∞);

(H2)Pis a Bernstein function,i.e.,P′is totally monotone(see Section 2 for definition);

Our first theorem states that by assuming(H1)–(H3),one can construct a ground state to(1.4)that fulfills desired qualitative properties.

Theorem 1.1(Existence of a ground state).Suppose(H1)–(H3).Let p ∈(1,(d+s)/(d ?s))be given. Then for anyμ>0,the generalizedNLS

possesses a ground state u ∈HP+μwhich is positive,radially symmetric and monotone decreasing in the radial direction.

The sign-definiteness of a ground state is naturally expected for the original NLS as a result of Hopf maximum principle enjoyed by second order elliptic PDEs. Here, we show that the minimizing property of a ground state and the strict positiveness of the fundamental solution of the operatorP(?Δ)+μgives the same consequence.

Theorem 1.2 (Sign-definiteness of a ground state).Suppose(H1)–(H3). Let p ∈(1,(d+s)/(d ?s))be given and u ∈HPμ be a ground state to(1.4).Then u0is either positive everywhere or negative everywhere.

The radial symmetry of a ground state is usually shown by the moving plain method [13] for standard NLS or by strict Riesz rearrangement inequality [17] for fractional NLS and pseudo-relativistic NLS.These methods do not seem to work without the explicit form ofP. As for uniqueness,a standard argument requires spectral information for the linearized operator at the ground state(see[4]). In[16],Lenzmann showed by a perturbative method that a(radial)ground state to pseudo-relativistic nonlinear Hartree equations (NLH for abbreviation) is unique for the small mass case. In [8], the authors developed,in a similar point of view,some perturbative arguments that show the uniqueness,up to a translation,of a(possibly non-radial)ground state to higher-order NLH.In the same spirit,we are able to show the symmetry and uniqueness of a ground state under more restrictive assumptions onPandpwhenμis sufficiently small. More precisely,we require that

We note that the choices ofP(0)=0 andP′(0)=1 in(H4)are just for numerical simplicity. Indeed,the assumption(H4)can be relaxed to

by a simple reformulation of Eq.(1.4).

Theorem 1.3 (Uniqueness of a ground state).Suppose(H1)–(H4). Let p ∈(1,d/(d ?s))be given and u ∈HPμ be a positive ground state to(1.4). Then there exists μ0> 0such that ifμ∈(0,μ0)then u is unique up to a translation.

The uniqueness result asserted in Theorem 1.3 is perturbative in nature. Indeed,the smallness of the massμis transferred to the smallness of?>0 in the equation plays an indispensable role in the proof.

Theorem 1.4(Existence of a radial solution forH1subcritical range ofp).Suppose(H1)–(H4). For any p ∈(1,(d+2)/(d ?2))and any q>d/s, there exists μ0> 0such that ifμ∈(0,μ0)then there exists a radially symmetric nontrivial solution u ∈Ws,q(Rd)to(1.4).

The rest of this paper is organized as follows.In Section 2,we introduce the concept of Bernstein functions and the properties of Fourier multiplier operators made by Bernstein symbols. In Section 3, we construct a nontrivial radial solution to (1.4) for small massμ>0 by using perturbation argument. Section 4 is devoted to the study of existence and qualitative properties on ground states to(1.4).

2 Preliminaries

2.1 Bernstein functions

A continuous functionf: [0,∞)→[0,∞)is said to betotally monotoneif it is smooth on(0,∞),and

for all nonnegative integernandλ> 0, wheref(n)is then-th derivative off. Totally monotone functions are an important class of functions in many areas of analysis. We refer the book[21]for a comprehensive overview. As for totally monotone functions,an important theorem is Bernstein’s theorem. It asserts that a totally monotone function is the Laplace transform of a Borel measure.

Theorem 2.1(Bernstein’s theorem[2]).If f:[0,∞)→[0,∞)is totally monotone,then there exists a non-negative Borel measureμon[0,∞)such that

From now on,we assume thatf: [0,∞)→[0,∞)andf′is totally monotone. Such a function is called aBernstein function. Note that the symbols(λ+m2)s ?m2s,0

This function space is equipped with the inner product

First,we prove that the symmetric decreasing rearrangement reduces the norm.

Proposition 2.1 (P′olya-Szeg¨o inequality).Suppose that f: [0,∞)→[0,∞)is a Bernstein function. Then,for any non-negative function u ∈Hf(Rd;R),we have

where u?is the symmetric decreasing rearrangement of u.

Proof.We claim that iffis a Bernstein function,thene?f(λ)is totally monotone. For the claim,it suffices to show that then-th derivative ofe?f(λ)is of the form(?1)ne?f(λ)gn(λ),wheregnis a(non-negative)totally monotone function. Whenn=0,it is obviously true withg0= 1. Suppose that the claim holds whenn=k. Then,the next order derivative ofe?f(λ)is(?1)k+1e?f(λ)gk+1(λ),where

By functional calculus,we write

Note that by the claim and Bernstein’s theorem,for eachs ≥0,there exists a non-negative Borel measureμssuch that Hence, insertingλ=?Δ, we see that the operatore?s f(?Δ)is the convolution of the radially symmetric,non-negative and decreasing function

Thus we complete the proof.

Next,we prove the symmetry and the positivity of the fundamental solution.

Proposition 2.2(Positivity of the fundamental solution).If f: [0,∞)→[0,∞)is a Bernstein function, then the fundamental solutionΦ = Φf for the differential operator f(?Δ)is radially symmetric,strictly positive and decreasing.Proof.It follows from

(2.1)and the heat kernel.

We also show that a real-valued function inHfcan be orthogonally decomposed into two functions having different signs.

Proposition 2.3 (Orthogonal decomposition).Suppose that f: [0,∞)→[0,∞)is a Bernstein function. Then, for any u ∈ Hf(Rd;R), there exist u± ∈ Hf(Rd;R)such that u=u+?u?,u± ≥0a.e. and〈u+,u?〉Hf(Rd;R)=0.

Proof.LetKbe the set of non-negative functions inHf(Rd;R),which is a closed convex non-empty cone inHf(Rd;R). Then, by Theorem 3.4 in [12] (see [19] for the original work),there exists a unique decompositionu=u1+u2,withu1∈Kandu2∈K?,such that〈u1,u2〉Hf(Rd;R)=0,whereK?is the dual cone ofKdefined by

It remains to show that everyw ∈K?is non-positive. Indeed,ifu ∈C∞c(Rd;R)is nonnegative,then by Proposition 2.2,so is Φ?u. Therefore,for anyw ∈K?,we have

However,sinceuis arbitrary,this proves thatwis non-positive.

2.2 Assumptions on the symbol P and its properties

Here we recall the structural assumptions for the symbolP:

(H1)P:[0,∞)→[0,∞)is continuous on[0,∞)and smooth on(0,∞);

(H2)Pis a Bernstein function,i.e.,P′is totally monotone;

(H4)P(0)=0,P′(0)=1 andP′′(0)exists.

The advantage of assuming (H2) is to provide a nice integral representation of the symbol from which several important properties in our analysis are deduced.

Lemma 2.1(Integral representation of the symbol).Suppose that the symbol P:[0,∞)→Rsatisfies(H2). Then,there exists a unique measureμon[0,∞)such that

As a consequence,if we further assume(H4),then the zeroth and the first moments of the measure is finite and

Proof.By the fundamental theorem of calculus,we have

By(H2),it follows from Bernstein’s theorem for complete monotone functions[21,Theorem 1.4]that

for some unique measureμon[0,∞). Therefore,inserting the integral formula forP′(λ)and then integrating in?,we obtain(2.2).

By(H2),the symbolPis sub-linear,and differentiation reduces the degree of the symbol.

Lemma 2.2(Properties of the symbol).Suppose that P:[0,∞)→Rsatisfies(H2).

(i) For all λ1,λ2≥0,we have P(λ1+λ2)≤P(λ1)+P(λ2).

(ii) For any integer k ≥0and λ ≥0,we have|P(k)(λ)|λ?kP(λ).

Proof.(i)By(2.2),we have

(ii)Differentiating(2.2)ktimes,we write

and then apply the elementary inequality

Thus we complete the proof.

3 Construction of a radial solution to the generalized NLS in H1 subcritical range of p

This section is devoted to prove Theorem 1.4. Consider a one-parameter family of nonlinear elliptic equations

whereP?(λ) =P(?λ)/λ. IfP′(0) exists, Eq. (3.1) formally converges to the nonlinear elliptic equation

We remark that Eq.(3.1)is possibly supercritical,since the differential operator may have a lower order than the Laplacian(see Lemma 2.2(i)).

In this section, we impose the hypotheses (H1)–(H4) on the symbolPto establish existence of a non-trivial solution to (3.1) by the contraction mapping argument in [6]provided that?is sufficiently small.

The following two lemmas will be employed in the contraction mapping argument.The first lemma asserts a certain coercivity of the Fourier multiplierP?(?Δ).

Lemma 3.1(Coercivity).Suppose that(H1)–(H3)hold for some s ∈(0,2]. Letμ> 0. Then,for any1

where‖·‖L(Lq;Ws,q)denotes the standard operator norm from Lq to Ws,q.

Proof.By the H¨ormander-Mikhlin theorem,it suffices to show that for all integerk ≥0,

withj1+···jm=k. We prove the claim by induction. The zeroth step is trivial. If the claim is true for thek-th step, then the (k+1)-th step follows, because when the derivative hits one of the fractions,it generates fractions of the same kind. Precisely,we have

The second lemma claims the convergenceP?(?Δ)→?Δ in the norm resolvent sense.

Lemma 3.2(Norm resolvent convergence ofP?).Suppose that(H1)–(H4)hold for some s ∈(0,2]. Letμ>0. Then,for any1

Proof.By the H¨ormander-Mikhlin theorem again,it suffices to show that

and by(3.4),we have

It is obvious that

and we have shown that

(see(3.4)). Thus,it remains to consider the last factor(λ ?P?(λ)). Indeed,differentiating(2.2)and using(2.3),one can show that

Therefore,collecting all,we complete the proof of(3.7).

3.1 Construction of a non-trivial solution

Now,we seek for a solution of the form near the ground state to the limit equation. Note that Theorem 3.1 below obviously includes Theorem 1.4.

Theorem 3.1(Existence and local uniqueness of a non-trivial solution).Suppose that(H1)–(H4)for some s ∈(0,2]. Assuming(3.3),let u0be the unique radially symmetric solution to the limit equation(3.2). Then,there exists small ?0>0such that Eq.(3.1)has a non-trivial radially symmetric solution u?∈Ws,q for all r ≥2. Moreover, u?is a unique radial solution in the neighborhood of u0with respect to the norm‖·‖Ws,q.

We insertu?=u0+w?,assuming that the differencew?is small. Then,reorganizing in the linearized form,the equation forw?is derived as

We claim that the linearized operator on the left hand side is invertible.

Lemma 3.3(Invertibility of the linearized operator).Suppose that(H1)–(H4)hold for some s ∈(0,2]. Then,for any q ∈[2,∞),there exists small ?0> 0such that if0

Proof.We write

where

Therefore,

is invertible onLqr, and its inverse is uniformly bounded. Therefore, inverting(3.9)and applying Lemma 3.1,we complete the proof.

We aim to find a solution to (3.10) by a contraction mapping argument. The following elementary inequality is helpful to handle the nonlinearity in the equation.

Lemma 3.4.If a>0and p>1,then

Proof.By the fundamental theorem of calculus,

If 1

we obtain the desired bound. Ifp> 2, we apply the fundamental theorem of calculus again to get

Therefore, there exists small?0> 0 (depending on the functionu0) such that for?∈(0,?0],

while ifp>2,

Collecting all, we conclude that Φ is contractive onBδ(0). Therefore, Eq. (3.10) (consequently,(3.1))has a unique solution inBδ(0).

4 Ground state for the generalized lower-order NLS

In this section we prove Theorems 1.1–1.3. Throughout this section,μdenotes a positive constant.

4.1 Variational settings

For a symbolPsatisfying(H1)–(H3),we consider the Hilbert spaceHP+μ=HP+μ(Rd;R).We note thatP+μis a Bernstein function because so isP. By(P2)and Sobolev embedding,one has a natural embedding

Then the functionalIgiven by

is well-defined andC1onHP+μ. It is clear that (1.4) is the Euler-Lagrange equation of(4.1).

We sayu0∈HP+μis a ground state to(1.4)ifu0is a critical point ofIandI(u0)≤I(v)for any nontrivial critical pointv ∈HP+μofI.

4.2 Existence of a ground state

In this subsection,we construct a ground state for the generalized NLS,which is positive,radially symmetric and monotone decreasing up to translation. We shall be done by establishing existence of a minimizer for the variational problem

Such a minimizer is of course a ground state for the generalized NLS,since every critical point ofIsatisfies the constraint.

The following lemma is trivial, but we write it as a lemma, because it will be used frequently.

Lemma 4.1.Suppose that u is admissible for the variational problem(4.2),i.e.,u/=0and

We assume that

Then,there exists t ∈(0,1]such that t?u is admissible and

If we further assume that either the inequality(4.3a)or(4.3b)holds strictly,then

Proof.Since

there existst ∈(0,1]such thatt?uis admissible,i.e.,

Therefore,by(4.3a),it follows that

If either(4.3a)or(4.3b)holds strictly,thent<1 andI(t?u)

Proof of Theorem1.1.By the constraint,

for admissibleu. Let{un}∞n=1?HP+μbe a minimizing sequence. For eachn, applying Proposition 2.3, we writeun=un,+?un,?such thatun,± ∈HP+μ,u± ≥0 and〈un,+,un,?〉HP+μ= 0. We define a new sequence{?un}∞n=1by ?un=un,++un,?≥|un|.Then,we have

Thus,it follows from Lemma 4.1 that there exists{tn}∞n=1?(0,1]such that{tn?un}∞n=1is also a minimizing sequence. Replacingunbytn?un,we assume thatunis nonnegative.

Letu?n, wheref?is the symmetric decreasing rearrangements off ≥0. Then, by P′olya-Szeg¨o inequality(Proposition 2.1)and the measure preserving property of the rearrangement,

Hence,by Lemma 4.1 again,we can find a sequence{tn}∞n=1?(0,1]such that{tnu?n}∞n=1is also a minimizing sequence. Replacingunbytnu?n,we assume thatunis radially symmetric and monotone decreasing.

We now have a minimizing sequence{un}∞n=1of nonnegative radially symmetric functions monotone decreasing in the radial direction. Hence,passing to a subsequence,{un}weakly converges to someuinHP+μ,which implies that

and{un}converges toua.e. This shows thatuis also nonnegative radial symmetric function monotone decreasing in radial direction.

This implies a positive lower bound of‖un‖HP+μ, which makes a contradiction. Thus,choosing appropriatet ∈(0,1]by Lemma 4.1 as above,we can maketuadmissible,and

Therefore,we conclude thattuis a minimizer.

We once more redefiningtuasuso thatuis a nonnegative ground state to(1.4)which is radially symmetric and decreasing in radial direction. It remains to show thatuis strictly positive everywhere. Let ΦP+μbe the fundamental solution of the differential operatorP(?Δ)+μ. By Proposition 2.2,it is strictly positive. Since the ground stateuis represented by

we see thatuis strictly positive. This completes the proof.

4.3 Sign-definiteness of a ground state

This subsection is devoted to prove Theorem 1.2,the sign-definiteness of a ground state to(1.4).

Proof of Theorem1.2.By Proposition 2.3,there are non-negativeu± ∈HP+μsuch thatu=u+?u?,〈u+,u?〉HP+μ= 0. We observe thatu+(x)u?(x) = 0 for allx ∈Rd. In other words,u+andu?have disjoint supports,

Indeed,if(4.4)does not hold,the function ?u=u++u?obeys‖?u‖2HP+μ=‖u‖2HP+μand

where the inequality holds strictly due to cross terms. Thus, it follows from Lemma 4.1 that there existst ∈(0,1]such thattuis admissible andI(tu)

Next,we claim that

To prove the claim,we note that by(4.4),the equality holds in(4.5).As a consequence,the function ?udefined previously is also a minimizer, so it is a solution to (1.4). Moreover,?u=|u|. For contradiction, we assume thatu+/= 0 andu?/= 0. Observe from the orthogonality ofu+andu?that

Then either

The strict inequality is due to the assumption thatu?/= 0. Sinceuis a minimizer, this makes a contradiction and the claim is proved. Finally, we have already seen in the proof of Theorem 1.1 that a nonnegative (nonpositive) minimizer is positive (negative)everywhere since the fundamental solution ΦP+μofP+μis strictly positive. This ends the proof.

4.4 Uniqueness of a ground state

Here, we prove Theorem 1.3. Throughout this subsection, we assume(H1)–(H4)on the symbolPhold. We fix arbitrarily chosenp ∈(1,d/(d ?s))and denote byu0the unique radial positive ground state to the original NLS,

As mentioned in Section 3,the generalized NLS

is equivalently transformed to

Lemma 4.2 (Convergence).Let v?∈HP?+1be a positive ground state to(4.9). Then there exists{a?}?Rd such that

Proof.The lemma is a natural consequence of energy minimality of the ground statesv?to(4.9). We refer to Proposition 2.3 in[8],with which their proof follows the exactly same lines. We omit the proof for avoiding the paper too lengthy.

Lemma 4.3 (Nondegeneracy).Let {v?} ?HP?+1be a family positive ground state to(4.9)such that{v?}converges to u0in HP?+1as ?→0. Define the linearized operator by

Then there exists a constant β>0independent of small ?>0such that

for any g ∈HP?+1which is HP?+1orthogonal to ?xiv?for each i=1,···,d.

Proof.This lemma can be proved in the same spirit with Lemma 3.3 but one should take care on the change of function spaces from the radial function space (Ws,qr →span{?xiv?|i= 1,···,d}⊥). This can be easily done by repeating the proof of Proposition 3.3 in[8]. We omit it.

Proof of Theorem1.3.Let{v?},{?v?} ?HP?+1be two families of positive radially symmetric ground states to (4.9). By Lemma 4.2, we may assume that both of{v?}and{?v?}converge tou0inHP?+1as?→0 by taking translations if necessary. This means that

Let{a?}?Rdbe a family of vectors such that

Then one has

since

We redefine ?v?(·?a?)by ?v?so that ?v?is still a ground state, ?v??v?is orthogonal to?xiv?inHP?+1and lim?→0‖v???v?‖HP?+1=0 by definition ofa?.

Let us definer?= ?v??v?. From Eq.(4.9),one has

so that by Lemma 4.3,

It is easy to see from (H3) that there exists a uniform constantC> 0 independent of?∈(0,1)such that

Then we invoke Lemma 3.4 and H¨older inequality to obtain

Combining this with(4.16)and using the fact that lim?→0‖r?‖HP?+1=0,we getr?=0 for sufficiently small?>0. This shows ?v?=v?and ends the proof.

Acknowledgements

This research of the first author was supported by Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Science and ICT(NRF-2020R1A2C4002615). This research of the second author was supported by Basic Science Research Program through the National Research Foundation of Korea(NRF)funded by the Ministry of Science and ICT(NRF-2020R1C1C1A01006415)