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    MULTIPLICITY OF POSITIVE SOLUTIONS FOR QUASI-LINEAR ELLIPTIC EQUATIONS INVOLVING CONCAVE-CONVEX NONLINEARITY AND SOBOLEV-HARDY TERM

    2019-09-21 00:09:28DUMingLIUXiaochun
    數(shù)學(xué)雜志 2019年5期

    DU Ming, LIU Xiao-chun

    (School of Mathematics and Statistics, Wuhan University, Wuhan 430072, China)

    Abstract: In this paper, we investigate the quasi-linear elliptic equations involving concaveconvex nonlinearity and Sobolev-Hardy term. By using the theory of the Lusternik-Schnirelmann category and the relationship between the Nehari manifold and fibering maps, we get some improvement on existence and multiplicity of positive solution.

    Keywords: subcritical Sobolev-Hardy exponent; Nehari manifold; sign-changing weight;concave-convex nonlinearity

    1 Introduction

    In this paper, we consider the following equation

    (A1)with f±(x) = ±m(xù)ax{±f(x),0}0 and there exists a positive constant rfsuch that

    (A2) g ∈C(RN) withand there exists constants rg1,rg2with 0

    and

    Such kind of problem arised from various fields of geometry and physics and was widely used in the applied sciences. We refer to [1–3] for details on the description about the background.

    Elliptic problems on bounded domains involving concave-convex nonlinearity were studied extensively since Ambrosetti, Brezis and Cerami [4] considered the following equation

    where 1 < q < 2 < p2?, μ > 0. They found that there exists μ0> 0 such that (1.2)admits at least two positive solutions for μ ∈(0,μ0), a positive solution for μ = μ0and no positive solution exists for μ > μ0(see also Ambrosetti, Azorero and Peral [5, 6] for more references therein). In recent years, several authors studied semilinear or quasilinear problems with the help of Nehari manifold (see [7–9]). In particular, Lin [9] studied the following critical problem

    where ? ?RN(N3) is a bounded domain with smooth boundary,and 1

    Actually,Fan and Liu[10]established multiple positive solutions of standard p-Laplacian elliptic equations without Hardy term on a bounded domain ? in RN. Some other theorems for p-Laplacian elliptic equations without Hardy term can be found in [11, 12]. Hsu and Lin[13] studied the following critical problem via generalized Mountain Pass Theorem [14]

    However, little is done on RNfor the operatorinvolving the concave-convex nonlinearity. Since the embedding is not compact on RNand the weight functions f and g are sign-changing, we will discuss the concentration behavior of solutions on the corresponding Nehari manifold to overcome these difficulties. Moreover,we get some improvement on multiplicity of positive solutions via the theory of Lusternik-Schnirelmann category (see [15]).

    Throughout our paper,we denote bythe completion ofwith respect to the standard norm. The functionis said to be a solution of problem (1.1) if u satisfies

    Then Iμ(u) is well-defined onand belongs to

    Problem (1.1) is related to well-known Caffarelli-Kohn-Nirenberg inequality in [16]

    If b=a+1, then p?(a,b)=p and the following Hardy inequality holds [17]

    which is equivalent to the usual norm

    We get our main result as follows.

    Theorem 1.1Suppose that the functions f and g satisfy condition(A1)and(A2). Let

    where Sλis the best Sobolev constant for the embedding ofinto Lr(RN) and defined by

    Then

    (i) for μ∈(0,L2), (1.1) has at least two positive solutions incorresponding to negative least energy;

    (ii) there exists μ0∈(0,L2) such that for μ ∈(0,μ0), (1.1) has at least three positive solutions inincluding two with positive energy.

    The paper is organized as follows: in Sections 2–4, based on some related preliminaries,we develop the description of Palais-Smale condition and the estimate of corresponding energy functional Iμ; in Section 5, we discuss the concentration behavior of solutions on Nehari manifold; in Section 6, we complete the proof of Theorem 1.1.

    2 Preliminaries

    Since the energy functional Iμin (1.6) is unbounded below onwe consider the functional on Nehari manifold

    Note that Nμcontains all nonzero solutions of (1.1) and u ∈Nμif and only if

    Lemma 2.1The energy functional Iμis coercive and bounded below on Nμ.

    ProofFor u ∈Nμ, by the H?lder inequality and Sobolev embedding theorem, we can deduce

    where C is a positive constant depending on N,q,Sλand. This completes the proof.

    Define

    Then for u ∈Nμ, we have

    As in [18], we divide Nμinto three parts

    Then we have the following result.

    Lemma 2.2

    ProofBy (2.1) we can easily derive these results.

    Then the following lemma is essential for the main result.

    Lemma 2.3(i) For all μ∈(0,L1), we haveand α+<0.

    (ii) If μ < L2, then we have α?> c0for some c0> 0. In particularfor all μ∈(0,L2).

    Proof(i) Suppose the contrary. We may assume that there exists μ?∈(0,L1) such thatThus,for each,by the H?lder and Sobolev inequalities,we can obtain

    that is,

    and so

    But (2.1) implies that

    which means

    Combined (2.4) and (2.5), we have

    This contradicts to μ?∈(0,L1). Therefore,andfor μ ∈(0,L1).

    and so

    or

    Then for μ∈(0,L2), we have

    wher e

    This implies, for μ∈(0,L2), α+<0

    Now we introduce the following function mu:R+→R in the form

    Clearly, tu ∈Nμif and only ifand

    It is obvious that if tu ∈Nμ, thenHence,if and only if(or <0).

    and mustrictly increases on (0,tmax) and decreases on

    Furthermore, since μ∈(0,L1), we have

    Thus, we have the following lemma.

    Lemma 2.4For each u ∈){0}, we have

    Proof(i) The equationadmits a unique solution t?>tmaxandholds by Lemma 2.3.

    (iii) By the uniqueness and extremal property of t?(u), we have t?(u) is a continuous function for u ∈

    Thus, the proof is completed.

    Remark 2.5If μ=0, by Lemma 2.4 (i),=?and so

    3 Palais-Smale Condition

    Now we consider the limiting problem

    and the corresponding energy functionalis defined by

    Proposition 3.1Forproblem (3.1) has radially symmetric ground states

    satisfying

    where ci(i=1,2) are positive constants and a(λ),b(λ) are the zeros of the function

    Furthermore, there exist the positive constants c3,c4such that

    ProofAs in [19], we can prove that the limiting problem (3.1) has radially symmetric ground states, by which Sλcan be achieved. Let u(ξ) be a radial solution to (3.1). Then we get that

    Set

    Then we can obtain the following system

    The rest of the proof follows exactly the same lines as that of the limiting problem (3.1) in[19], here we omit it.

    By Proposition 3.1, we can easily derive the minimizing problem

    where

    For our purpose,the functional Iμis said to satisfy the(P.S.)ccondition if any sequencesuch that as n →∞,

    contains a convergent subsequence inThen the following proposition develops a precise description for the (P.S.)c-sequence of Iμ.

    Proposition 3.2(i) If μ∈(0,L1), then Iμhas a (P.S.)α-sequence

    (ii) If μ∈(0,L2), then Iμhas a (P.S.)α?-sequence

    ProofThe proof is similar to the argument of Proposition 3.3 in [20].

    Now, we establish the existence of a local minimizer for Iμon Nμ.

    Proposition 3.3Forμ∈(0,L1),the functional Iμhas a minimizersatisfying

    ProofBy Proposition 3.2 (i), there exists a minimizing sequence {un}n∈N?Nμsuch that

    where o(1) →0 as n →∞. Since Iμis coercive on Nμ, we get that {un} is bounded inIf necessary to a subsequence, there existssuch that as n →∞,

    Moreover, by the Egorov Theorem and Hlder inequality, we have

    Consequently, passing to the limit in, by (3.7) and (3.8), we have

    Furthermore, since un∈Nμ, we can deduce that

    which implies that

    Next, we will show, up to a subsequence, thatstrongly inandIn fact, by the Fatou’s lemma, it follows that

    which is a contradiction. Sinceand, we may assume thatis a nontrivial nonnegative solution of (1.1). By Harnack inequality, it follows thatin RN.

    Finally, by (2.1) and the H?lder inequality, we can obtain

    Let ul=u0(x+le),for l ∈R and e ∈SN?1,where u0(x)is a radially symmetric positivesolution of (3.1) such that Then we have the following result.

    Lemma 3.4

    We refer to the argument of Lemma 4.2 in He and Yang (see [21]).

    4 The Estimates of Energy

    The following statement is paramount to prove our main result.

    Proposition 4.1For μ∈(0,L2), we have

    ProofLetbe a positive solution of (1.1) in Proposition 3.3. Then we obtain

    Since

    and

    There exist 0

    Thus we only need to show that there exists l0>0 such that for l>l0, we have

    For u,v >0, we can remark that (u+v)r?ur?vr0, and so

    From condition (A1), (A2) and (3.5), we can obtain

    and

    Since 0 < rg2< min{rf?N,rg1?N} and t1tt2, by (4.1)–(4.8), we can find l0> 0 such that

    In order to complete the proof of Proposition 4.1, it remains to show that there exists a positive number t?such that. Let

    Next we claim that there exists t0> 0 such thatIn fact, we find a constant c > 0 such thatfor each t > 0. If not, then we may assume that there exists a sequence {tn}n∈Nsuch that tn→∞and

    Then we have

    which contradicts the fact that Iμis bounded below on Nμ. Let

    By (4.4) and Lemma 3.4, we have, as l →∞,

    Thus there exists l0>0 such that for l>l0, we get

    Then we have the following result.

    Theorem 4.2For μ ∈(0,L2), (1.1) has a positive solutionsuch that

    ProofBy Ekeland’s variational principle [22], there exists a minimizing sequencesuch that

    5 Concentration Behavior

    In this section, we discuss the concentration behavior of solutions to (1.1) so that we can get the proof of Theorem 1.1 (ii).

    Lemma 5.1We have

    Furthermore,(1.1)does not admit any solution w0∈such that I0(w0)=

    ProofBy Lemma 2.4, there exists the unique t?(ul) > 0 such that t?(ul)ul∈N0for all l>0, that is,

    Since

    and

    By (5.2)–(5.4), we have t?(ul)→1 as l →∞. Thus

    Then we can obtain

    For u ∈N0, by Lemma 2.4 (i),

    Moreover, there exists a unique t∞>0 such that t∞u ∈N∞. Thus,

    In order to show that (1.1) does not admit any solution w0such thatwe argue by the contrary. By Lemma 2.4(i), we haveMoreover, there exists a unique tw0>0 such that tw0w0∈N∞. Thus we obtain

    By the Lagrange multiplier and the maximum principle, we may assume that tw0w0is a positive solution of (1.1). This contradiction completes the proof.

    Lemma 5.2Assume that {un} is a minimizing sequence in N0for I0. Then

    Furthermore, {un} is a (P.S.)

    ProofFor each n, there exists a unique tn>0 such that tnun∈N∞, that is,

    By Lemma 2.4 (i), we have

    and

    Next, we will show that there exists M > 0, c0> 0 such that tn> c0for n > M. Suppose the contrary. Then we may assume tn→0 as n →∞. As in the proof of Lemma 2.3, we know thatis uniformly bounded and so→0 or I∞(tnun)→0. This contradicts the factfrom Lemma 5.1. Then we have

    and

    This implies

    andso

    Let

    be the filtration of the Nehari manifold Nμ. Then we have the following lemmas.

    Lemma 5.3There exists d0<0 such that for u ∈N0(d0), we have

    ProofSuppose the contrary. We may assume that there exists a sequence {un}n∈N?N0such thato(1). By Proposition 3.2 and the concentration-compactness principle (see [23, Theorem 4.1]), there exists a sequence {xn}n∈N?RNsuch that

    Now we will show that |xn|→∞as n →∞by contradiction. We may assume that {xn} is bounded and xn→x?for some x?∈RN. Then by (5.11),

    this contradicts the result of Lemma 5.2 (i). Hence we may assumee as n →∞,where e ∈SN?1. By the Lebesgue dominated convergence theorem, we have

    This contradiction completes the proof.

    By (2.1) and Lemma 2.4 (i), for eachthere exists the uniquesuch thatandThen we have the following result.

    Lemma 5.4Let

    For each μ∈(0,L2) and, we have

    ProofForwe distinguish from the following distinctive cases.

    Case(i)Since T >1, we have

    Case(ii)Since

    and by Lemma 2.2 (iii), we have

    Moreover, from the argument in the proof of Lemma 2.2, we have

    Thus, by (5.12)–(5.14), we have

    This completes the proof.

    Lemma 5.5There exists μ0∈(0,L2) such that for each μ∈(0,μ0) and

    ProofForby Lemma 2.4 (i), there existssuch thatN0. Moreover, by Lemma 5.4 and the H?lder inequality and Sobolev embedding theorem,we have

    or so

    by Lemma 2.1, for μ ∈(0,L2) and, there exists c?independent of μ such thatThus,

    Then by Lemma 5.3, we have

    and this implies

    The proof is completed.

    6 Proof of Theorem 1.1

    In this section, we will follow an idea in [24] to prove our main result. For c ∈R+, we denote

    Then we try to show that for a sufficiently small σ >0, we have

    Here‘cat’means the Lusternik-Schnirelmann category[15]. First,let us recall its definition.

    Definition 6.1A non-empty, closed subset Y is contractible in a topological spaceXif there exists h ∈C([0,1]×Y,X) such that for some x0∈X,

    Definition 6.2Let Y1,Y2,··· ,Ykbe closed subsets of a topological spaceX. The category ofXis the least integer k such that Yjis contractible inXfor all j anddenoted by cat(X).

    When there do not exist finitely many closed subsets Y1,Y2,··· ,Yk?Xsuch that Yjis contractible inXfor all j and=X, we denote cat(X)=∞. We need the following lemmas (see Theorem 2.3 in [25] and Lemma 2.5 in [24]).

    Lemma 6.3LetXbe a Hilbert manifold and F ∈C1(X,R). Assume that there are c0∈R and k ∈Nsuch that

    (i) F satisfies the Palais-Smale condition for energy level

    Then F has at least k critical points in

    Lemma 6.4LetXbe a topological space. Assume that there are ? ∈C(SN?1,X)and ψ ∈C(X,SN?1) such that ψ ?? is homotopic to the identity map of SN?1, that is,there exists h ∈C([0,1]×SN?1,SN?1) such that h(0,x) = (ψ ??)(x), h(1,x) = x. Then cat

    For l>l0, we define a mapby

    Lemma 6.5There exists a sequence {σl}?R+with σl→0 as l →∞such that

    ProofBy Proposition 4.1, for l>l0, we haveand

    Since ?μ(SN?1)is compact andthe conclusion holds.

    From Lemma 5.5, we define a barycenter map,by

    Then we have the following result.

    Lemma 6.6Letμ0be as in Lemma 5.5. Then forμ∈(0,μ0),there exists l?>l0such that the map

    is homotopic to the identity operator.

    ProofDenote

    as an extension of ψμ. Since ul∈supp ψμfor all e ∈SN?1and large enough l, we may assume γ :[s1,s2]→SN?1is a regular geodesic between ψμ(ul) andsuch that

    By an argument similar to Lemma 5.3, there exists l?l0such that

    for all e ∈SN?1, l>l?and θ ∈We define

    by

    as θ →1?.

    and

    for all e ∈SN?1and l>l?. This completes the proof.

    Lemma 6.7For μ ∈(0,μ0) and l > l?, the energy functional Iμadmits at least twocritical points in

    ProofIt is easy to deduce from Lemmas 6.3, 6.4, 6.6 and Proposition 3.2.

    Proof of Theorem 1.1Now we can complete the proof of Theorem 1.1

    (i) by Proposition 3.3 and Theorem 4.2;

    (ii) from Proposition 3.3 and Lemma 6.7, (1.1) has at least three positive solutions

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