Yueshan Wangand Yuexiang He
Department of Mathematics,Jiaozuo University,Jiaozuo 454003,Henan,China
Abstract.Let L=??+V be a Schr?dinger operator on Rn(n ≥3),where the nonnegative potential V belongs to reverse Ho?der class RHq1 for Let be the Hardy space associated with L.In this paper,we consider the commutator[b,Tα],which associated with the Riesz transform with 0<α ≤1,and a locally integrable function b belongs to the new Campanato space We establish the boundedness of[b,Tα]from Lp(Rn)to Lq(Rn)for 1
Key Words:Riesz transform,Schr?dinger operator,commutator,Campanato space,Hardy space.
Let L=??+V be a Schr?dinger operator on Rn,where n≥3.The function V is nonnegative,and belongs to a reverse H?lder class RHq1for some q1>n/2,that is to say,V satisfies the reverse H?lder inequality
for all ball B?Rn.We consider the Riesz transform Tα=Vα(??+V)?α,where 0<α≤1.
Many results about Tα=Vα(??+V)?αand its commutator have been obtained.Shen[1]established the Lp-boundedness of T1and T1/2,Liu and Tang[2]showed that T1and T1/2are bounded onforFor 0<α≤1,Sugano[3]studied the Lp-boundedness and Hu and Wang[4]obtained theboundedness.When b ∈BMO,Guo,Li and Peng[5]obtained the Lp-boundedness of commutators[b,T1]and[b,T1/2],Li and Peng in[6]proved that[b,T1]and[b,T1/2]map continuouslyinto weak L1(Rn).When b ∈BMOθ(ρ)and 0<α ≤1,the Lp-boundedness of[b,Tα]was investigated in[7]and the boundedness frominto weak L1(Rn)given in[4].
In this paper,we are interested in the boundedness of[b,Tα]when b belongs to the new Campanato classLet us recall some concepts.
As in[1],for a given potential V∈RHq1with q1>n/2,we define the auxiliary function
It is well known that 0<ρ(x)<∞for any x∈Rn.
Let θ>0 and 0<β<1,in view of[8],the new Campanato classconsists of the locally integrable functions b such that
for all x∈Rnand r>0.A seminorm ofdenoted byis given by the infimum of the constants in the inequalities above.
We recall the Hardy space associated with Schr?dinger operator L,which had been studied by Dziubański and Zienkiewicz in[10,11].Becausethe Schr?dinger operator L generates a(C0)contraction semigroupThe maximal function associated with{:s>0}is defined by.we always denote δ'=min{1,2?n/q1}.ForWe say that f is an element ofif the maximal function MLf belongs to Lp(Rn).The quasi-norm of f is defined by
We now formulate our main results as follows.
Theorem 1.1.Let V ∈RHq1with q1>n/2,and letIf 0<α ≤1 andthen
We immediately deduce the following result by duality.
Corollary 1.1.Let V ∈RHq1with q1>n/2,and letIf 0<α≤1 and 1
where 1/q=1/p?β/n.
Theorem 1.2.Let V ∈RHq1with q1>n/2,and let 0<α≤1.Supposeand 0<β<δ'.Ifandthen the commutator[b,Tα]is bounded frominto
Theorem 1.3.Let V ∈RHq1with q1>n/2,and let 0<α ≤1.Suppose0<β<δ'.
Then the commutator[b,Tα]is bounded frominto weak L1(Rn).
We recall some important properties concerning the auxiliary function.
Proposition 2.1(see[1]).Let V ∈RHn/2.For the function ρ there exist C and k0≥1 such that
for all x,y∈Rn.
Assume that Q=B(x0,ρ(x0)),for any x∈Q,Proposition 2.1 tell us thatif|x?y| Lemma 2.1.Let k∈N andThen we have Lemma 2.2(see[11]).Suppose V∈RHq1,q1≥n/2.Then there exists constants C>0 and l0>0 such that The following finite overlapping property given by Dziubański and Zienkiewicz in[10]. Proposition 2.2.There exists a sequence of pointsin Rn,so that the family of critical ballsk≥1,satisfies (ii)There exists N=N(ρ)such that for every k∈N,card where Bρ,α={B(z,r):z∈Rnand r≤αρ(y)}. We have the following Fefferman-Stein type inequality. Proposition 2.3(see[9]).For 1 We have an inequality for the function Lemma 2.3(see[8]).Let 1≤s<∞,,and B=B(x,r).Then for all k∈N,where θ'=(k0+1)θ and k0is the constant appearing in Proposition 2.1. Let Kαbe the kernel of(??+V)?α.The following results give the estimates on the kernel Kα(x,y). Lemma 2.4(see[4,12]).Suppose V ∈RHq1with (i)For every N>0,there exists a constant C such that (ii)For every 0<δ<δ' there exists a constant C such that for every N>0,we have where|y?z|≤|x?y|/4. Proposition 2.4(see[13]).Suppose that V ∈RHq1withLet 0<β2≤β1≤1,1 Let β1=β2=α,by Proposition 2.4 and duality we get Corollary 2.1.Suppose that V ∈RHq1withLet 0<α≤1 To prove Theorem 1.1,we need the following Lemmas. Lemma 3.1.Suppose V ∈RHq1withandIfthen for all f ∈and every critical ball Q=B(x0,ρ(x0)),we have where Proof.Since then where f=f1+f2with f1=f χ2Q. By the Ls-boundedness of(Corollary 2.1),we have By Lemma 2.4, For any y∈Q and z∈(2Q)c,we haveandSo,decomposing(2Q)cinto annuliwe get Then Thus,taking N>l0α we get The estimate for I2can be proceeded in the same way of I1.The decomposition f=f1+f2gives Lemma 3.2.Let B=B(x0,r)with r≤γρ(x0)and let x∈B,then for any y,z∈B we have Proof.Setting Q=B(x0,γρ(x0)),due to the factandthen by Lemma 2.4 we get where and Let j0be the least integer such thatSplitting into annuli,we have For K2,splitting into annuli, Thus,we complete the proof. Lemma 3.3.Letlet B=B(x0,r)with r≤γρ(x0)and let x∈B.Then Proof.Write where f=f1+f2with f1=f χ2B. Since r≤γρ(x0)and ρ(x)≈ρ(x0),by H?lder’s inequality and Lemma 2.3,we get Select r0so thatthen by Ho?der’s inequality and Lemma 2.3, By Lemma 3.2, So,we complete the proof. We now come to prove Theorem 1.1.By Proposition 2.3,Lemma 3.1 and Lemma 3.3 we have where we have used the finite overlapping property given by Proposition 2.2. We have the following atomic characterization of Hardy space. Definition 4.1.LetA function a ∈L2(Rn)is called an-atom if r<ρ(x0)and the following conditions hold: (i)supp a?B(x0,r), (iii)if r<ρ(x0)/4,then Proposition 4.1(see[11]).LetThenif and only if f can be written aswhere ajare-atoms,and the sum converges in thequasi-norm.Moreover where the infimum is taken over all atomic decompositions of f into-atoms. Let us prove Theorems 1.2.Choose τ such thatBy Proposition 4.1,we only need to show that for any-atom a, holds,where C is a constant independent of a. Suppose supp a?B=B(x0,r)with r<ρ(x0).Then Let 1/t=1/τ?β/n.By Corollary 1.1 and the size condition of atom a,we have For A2,we consider two case,that are r<ρ(x0)/4 and ρ(x0)/4≤r<ρ(x0). Case I:When r<ρ(x0)/4,by the vanishing condition of a,we have Note that For x∈2k+1B2kB,y∈B,we have|x?y|≈2kr.Then by Lemma 2.4 and Lemma 2.1, Choosing s such that αq Then,by Minkowiski’s inequality and taking N>l0α(k0+1),we get Case II:When ρ(x0)/4≤r<ρ(x0),this means r ≈ρ(x0).The atom a does not satisfy the vanishing condition.By Minkowiski’s inequality, Note r≈ρ(x0),then by(4.1),(4.2)and(4.3)we get Suppose that suppaj?Bj=B(xj,rj)with rj<ρ(xj).Write Note that Then Then Thus,by the vanishing condition of ajand 0<β<δ<δ'we have Therefore Note that and By Corollary 2.1,we know that Tαis bounded from L1(Rn)to WL1(Rn),then Thus, Thus,we complete the proof of Theorem 1.33 The Lp-boundedness of[b,Tα]
4 The -boundedness of[b,Tα]
Analysis in Theory and Applications2018年4期